How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?
1/5x-2=1/3x+8
times both sides by 15
3x-30=5x+120
minus 3x both sides
-30=2x+120
minus 120 both sides
-150=2x
divide both sides by 2
-75=x
Answer:
\(y=\frac{1}{5}x-2\)
\(y=\frac{1}{3}x+8\)
Step-by-step explanation:
Given equation,
\(\frac{1}{5}x-2=\frac{1}{3}x+8\)
∵ When we solve an equation with help of graphing,
Then we make a system of equations by equating left side of the equation to a variable ( generally we put y ) and right side of the equation to the same variable,
Thus, by the statement,
The system of equation for solving the above equation would be,
\(y=\frac{1}{5}x-2\)
\(y=\frac{1}{3}x+8\)