Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(195)(pp)(q^-2q^6) = ?
195 is 95.
For pp remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of pp) they are always assumed to be 1. So what is 1+1? 2.
pp is p^2
For q^-2q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
