Verified Answer :
Answer:
The impulse is 21.41 kg-m/s.
Explanation:
Given that,
Mass of stone = 2.50 kg
Height = 3.75 m
We need to calculate the time
Using equation of motion
\(s=ut+\dfrac{1}{2}gt^2\)
Where, s = height
u = initial speed
t = time
Put the value in the equation
\(3.75=0+\dfrac{1}{2}\times9.8\times t^2\)
\(t^2=\dfrac{3.75\times2}{9.8}\)
\(t=\sqrt{\dfrac{3.75\times2}{9.8}}\)
\(t=0.874\ sec\)
We need to calculate the impulse
Using formula of impulse
\(J=F\times t\)
\(J=mg\times t\)
Put the value into the formula
\(J=2.50\times9.8\times0.874\)
\(J=21.41\ kg-m/s\)
Hence, The impulse is 21.41 kg-m/s.
The impulse gravity impart to this stone from the instant it is dropped until it hits the ground is 21.41 kg-m/s.
What is an impulse?
The impulse is defined as the effect of the force over a time. Like if you fall in a hard surface then force will be higher as compared to if you fall on a soft net. In soft net, the time increases and the effect of force decreases.
It is given that,
Mass of stone = 2.50 kg
Height = 3.75 m
We need to calculate the time
Using equation of motion
\(s=ut + \frac{1}{2} at^2\)
Where, s = height
u = initial speed
t = time
Put the value in the equation
\(3.75=0+\frac{1}{2} \times 9.8\times t^2\)
\(t=\sqrt{\dfrac{3.75\times 2}{9.8}\)
\(t=0.874\ sec\)
We need to calculate the impulse
Using formula of impulse
\(J=F\times t\)
\(J=mg\times t\)
Put the value into the formula
\(J=2.5\times 9.8\times 0.874\)
\(J=21.41 \ kg-\frac{m}{s}\)
Hence,the impulse gravity impart to this stone from the instant it is dropped until it hits the ground is 21.41 kg-m/s.
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