When a power is negative it can be written as one over number raised to the power ( 5\(^{-2}\) = \(\frac{1}{5^{2} }\))
∴ (4 ÷ 3)\(^{-2}\) = \(\frac{1}{( \frac{4}{3})^{2} }\)
= \(\frac{1}{ \frac{16}{9} }\)
= 1 ÷ \(\frac{16}{9}\)
= 1 × \(\frac{9}{16}\)
Thus (4 ÷ 3)\(^{-2}\) = \(\frac{9}{16}\)
