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A law firm has ten senior and eleven junior partners. A committee of 8 partners is selected at random to represent the firm at a conference. What is the probability that at least one of the junior partners is on the committee?

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The probability that none of the junior partners is selected is given by:
\(\frac{10C8}{21C8}=\frac{1}{4522}\)
Therefore the probability that at least one junior partner is selected is:
\(1-\frac{1}{4522}=\frac{4521}{4522}=0.99978\)
The answer is 0.99978

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