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the second term in a geometric sequence is 50. The fourth term in the same sequence is 112.5. what is the common ratio in the sequence?

Verified Answer :

geometric sequence

\(a_n=a1r^{n-1}\)
r=common ratio
a1=first term
n=which term

2nd term is 50
4th is 112.5

\(a_2=a1r^{2-1}\)=50
\(a_2=a1r^{4-1}\)=112.5

50=\(a1r^{1}\)
112.5=\(a1r^{3}\)

therefor
112.5/50=\(\frac{a1r^3}{ar^1} =r^2\)=2.25
r^2=2.25
sqrt both sides
r=1.5

the common ratio is 1.5

Answer:

1.5 apex answer