The sum of three consecutive integers is 3,009. What is the smallest of these integers?
1002
The equation ( x + 1 ) + ( x + 2 ) + ( x + 3) = 3009
We do 1 + 2 + 3 = 6
Subtract 3009 with 6 = 3003
We have 3x = 3003
Divide 3003 / 3 = 1001
x = 1001
Let's use our equation!
1002 + 1003 + 1004 = 3009
Consecutive integers are integers that have a difference of 1
The smallest of the integers is 1002
Let the smallest integer be x. So, the other integers are:
The sum is 3009. So, we have:
\(x + x + 1 + x + 2 = 3009\)
Collect like terms
\(x + x + x = 3009-1-2\)
Evaluate the like terms
\(3x = 3006\)
Divide both sides by 3
\(x = 1002\)
Hence, the smallest of the integers is 1002
Read more about consecutive numbers at:
https://brainly.com/question/10853762