[02.05] Solve for x: −3x + 3 < 6
-3x+3<6
minus 3 both sides
-3x<3
divide both sides by -3, don't forget to flip sign
x>-1
Answer:
x>-1
Step-by-step explanation:
The given inequality is \(-3x+3<6\)
Subtract 3 to both sides of the inequality
\(-3x<6-3\\\\-3x<3\)
Now, divide both sides by -3. Whenever, we divide/multiply both sides by a negative number then the inequality sign gets reversed. Thus, we have
\(\frac{-3x}{-3}>\frac{3}{-3}\\\\x>-1\)
Hence, the solution is x>-1