this is not fun
so
we mutiply the number of rows of the first matrix by the number of collumns of the second matrix
3*2 is the dimentions of the resulting matrix
you have
\(\left[\begin{array}{cccc}9&4&8&6\\2&0&3&1\\1&-2&5&0\end{array}\right]
\left[\begin{array}{cc}12&2\\15&1\\3&9\\8&11\end{array}\right]
=\)\(\left[\begin{array}{cc}9*12+4*15+8*3+6*8&9*2+4*1+8*9+6*11\\2*12+0*15+3*3+1*8&2*2+0*1+3*9+1*11\\1*12+-2*15+5*3+0*8&1*2+-2*1+5*9+0*11\end{array}\right]\)=\(\left[\begin{array}{cc}108+60+24+48&18+4+72+66\\24+0+9+8&4+0+27+11\\12+-30+15+0&2+-2+45+0\end{array}\right]\)=\(\left[\begin{array}{cc}240&160\\41&42\\-3&45\end{array}\right]\)
