Karen calculates the volume of cylinder A with a radius of 3 inches, and a height of 6 inches. The volume of this cylinder is 54π in3. Cylinder B also has a radius of 3 inches, but the height is doubled. What is the relationship between the volumes of the two cylinders?
the volume of B is twice that of A
if Vb=2hpir^2
and Va=hpir^2
compare
2hpir^2
hpir^2
twic as big
Volume of B is 2 times that of Volume of A
Answer:
\(2(\text{Volume of cylinder A})= \text{Volume of cylinder B }\)
Step-by-step explanation:
Cylinder A:
Radius = 3 inches
Height = 6 inches
Volume = \(54\pi inches^3\)
Cylinder B:
We are given that Cylinder B also has a radius of 3 inches, but the height is doubled.
Radius = 3 inches
Height = \(2 \times 6 =12\) inches
Volume of cylinder B = \(\pi r^{2} h\)
= \(\pi (3)^{2} \times 12\)
= \(108 \pi inches^3\)
Thus the volume of cylinder B is 108π cubic inches
Volume of Cylinder A = 54 π cubic inches
Since \(2(54\pi )=108\pi\)
So, twice the volume of cylinder A = Volume of cylinder B
\(2(\text{Volume of cylinder A})= \text{Volume of cylinder B }\)
Hence the relationship between the volumes of the two cylinders is \(2(\text{Volume of cylinder A})= \text{Volume of cylinder B }\)