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Verified Answer :

ANSWER

The solution is

\(x = 5\)
EXPLANATION


We want to solve the logarithmic equation

\(log_{2}(3x - 7) = 3\)
We take the antilogarithm of both sides to base 2.


In order words we need to rewrite the logarithmic equation as an exponential equation,

This implies that,


\((3x - 7) = {2}^{3}\)


We evaluate the right hand side of the equation to obtain,


\(3x - 7 = 8\)


We group the constant terms on the left hand side of the equation to obtain,


\(3x = 8 + 7\)

This implies that

\(3x=15\)

\(x = 5\)

The equation is a logarithm equation, and the solution to log₂(3x - 7) = 3 is x = 5

How to determine the solution?

The equation is given as:

log₂(3x - 7) = 3

Remove the logarithm symbol

3x - 7 = 2^3

Evaluate the exponent

3x - 7 = 8

Add 7 t both sides

3x = 15

Divide both sides by 3

x = 5

Hence, the solution to log₂(3x - 7) = 3 is x = 5

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