What is the solution of log2 (3x - 7) = 3?
ANSWER
The solution is
\(x = 5\)
EXPLANATION
We want to solve the logarithmic equation
\(log_{2}(3x - 7) = 3\)
We take the antilogarithm of both sides to base 2.
In order words we need to rewrite the logarithmic equation as an exponential equation,
This implies that,
\((3x - 7) = {2}^{3}\)
We evaluate the right hand side of the equation to obtain,
\(3x - 7 = 8\)
We group the constant terms on the left hand side of the equation to obtain,
\(3x = 8 + 7\)
This implies that
\(3x=15\)
\(x = 5\)
The equation is a logarithm equation, and the solution to log₂(3x - 7) = 3 is x = 5
The equation is given as:
log₂(3x - 7) = 3
Remove the logarithm symbol
3x - 7 = 2^3
Evaluate the exponent
3x - 7 = 8
Add 7 t both sides
3x = 15
Divide both sides by 3
x = 5
Hence, the solution to log₂(3x - 7) = 3 is x = 5
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