bewellplus.gsu.edu
mwickerh mwickerh
  • 19-11-2014
  • Mathematics
Answered

solve and check for extraneous solutions.

\(\sqrt{3x+1} =x-1\)

Verified Answer :

konrad509
konrad509 konrad509
  • 19-11-2014

\(D:3x+1\geq 0\wedge x-1\geq 0\\ D:3x\geq-1 \wedge x\geq1\\ D:x\geq-\frac{1}{3} \wedge x\geq1\\ D:x\geq1\\ \sqrt{3x+1}=x-1\\ 3x+1=(x-1)^2\\ 3x+1=x^2-2x+1\\ x^2-5x=0\\ x(x-5)=0\\ x=0 \vee x=5\)

The solution is 5.
The extraneous solution is 0.

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