if f(x)=4x-8, what is f^-1(x)
x = 4x - 8let's replace x with y. y = 4x - 8 y + 8 = 4xx = y/4 + 8/4x = y/4 + 2and now replace y with x.so x = x/4 + 2and inverse f^-1 f^-1 (x) = x/4 + 2