What is the mass percent of aluminum in Al(OH)3 the molar mass of AL = 26.98, H = 1.0079, and O = 16.00
mass percentage = (mass of Al)/(Total mass) 100
= (26.98) / (26.98 + 3 (1.0079 + 16)) * 100
= 34.59%
Answer: 34.58%
Explanation:-
Mass percentage is the ratio of mass of a particular element present in the total mass of the substance in terms of percentage.
\(Mass\ %=\frac{\text{Mass of} Al}{\text{Mass of} Al(OH)_3}\times 100\ %\)
Given: mass of AL = 26.98, H = 1.0079, and O = 16.00
Thus mass of \(Al(OH)_3=26.98+3\times 16+3\times 1.0079=78.0037g\)
Putting the values in the equation:
\(Mass\%=\frac{26.98g}{78.0037g/mol}\times 100\ %=34.58\ %\)
Thus mass percent of aluminum in \(Al(OH)_3\) is 34.58%.