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\(y=-5x^{-1}\)
\(\frac{dy}{dx}=\frac{5}{x^{2}}\)
The instantaneous slope at x = 5 is 1/5.

The answer is 1/5.

Answer:

Instantaneous slope  is \(\frac{1}{5}\)

Step-by-step explanation:

the instantaneous slope of y=-5\x at x=5

\(y=\frac{-5}{x}\)

To find instantaneous slope we take derivative of y

Derivative of 1/x is -1/x^2

\(y'=\frac{5}{x^2}\)

We need to find out instantaneous slope at x=5

so we plug in 5 for x in y'

\(y'=\frac{5}{x^2}\)

\(y'=\frac{5}{5^2}\)

\(y'=\frac{5}{25}\)

\(y'=\frac{1}{5}\)

Instantaneous slope  is \(\frac{1}{5}\)