what is the instantaneous slope of y=-5\x at x=5
\(y=-5x^{-1}\)
\(\frac{dy}{dx}=\frac{5}{x^{2}}\)
The instantaneous slope at x = 5 is 1/5.
The answer is 1/5.
Answer:
Instantaneous slope is \(\frac{1}{5}\)
Step-by-step explanation:
the instantaneous slope of y=-5\x at x=5
\(y=\frac{-5}{x}\)
To find instantaneous slope we take derivative of y
Derivative of 1/x is -1/x^2
\(y'=\frac{5}{x^2}\)
We need to find out instantaneous slope at x=5
so we plug in 5 for x in y'
\(y'=\frac{5}{x^2}\)
\(y'=\frac{5}{5^2}\)
\(y'=\frac{5}{25}\)
\(y'=\frac{1}{5}\)
Instantaneous slope is \(\frac{1}{5}\)