The legs of a right-angle triangle are perpendicular.
The slope of line ST must be -1/3
From the question, we have:
\(\mathbf{m_{RS} = 3}\) --- the slope of RS
Because line ST is the other leg of the right-angle triangle, then the slope of line ST is:
\(\mathbf{m_{ST} = -\frac 1{m_{RS}}}\)
Substitute \(\mathbf{m_{RS} = 3}\)
\(\mathbf{m_{ST} = -\frac 13}\)
Hence, the slope of line ST must be -1/3
Read more about slopes of perpendicular lines at:
https://brainly.com/question/10431875
