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shakalarobinson shakalarobinson
  • 05-10-2016
  • Mathematics
Answered

convert to standard circle form \(x^{2} +y ^{2} -6x-4y-12=0\)

Verified Answer :

Panoyin
Panoyin Panoyin
  • 05-10-2016

x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25

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