A round silo is 60 feet tall and has a 15 foot radius. about how high would a load of 32,000 ft³ of grain fill the silo to?
find volume
v=hpir^2
v=60pi15^2
v=60pi225
v=13500pi
v=42411.492=full
find wha fraction 32000 is
32000/42411.492=0.75451247
times that by height
60*0.75451247=45.2707487
about 45 feet
Answer:
A load of 32000 cubic feet fill the silo to height 45.252 feet.
Step-by-step explanation:
Height of silo = 60 feet
Radius of silo = 15 feet
Suppose silo in in the shape of cylinder
Volume of grain in silo =\(\pi r^2 h = \frac{22}{7} \times 15^2 \times h\)
Volume of grain in silo = \(32000 ft^3\)
\(\frac{22}{7} \times 15^2 \times h =32000\\h=\frac{32000 \times 7}{22 \times 15^2}\)
h=45.252 feet
Hence A load of 32000 cubic feet fill the silo to height 45.252 feet.