What is the mass of 3.8 × 10^24 atoms of argon (ar)? 0.0039 g 0.16 g 6.3 g 250 g
Atomic mass Ar => 39.948 a.m.u
39.948 g --------------- 6.02x10²³ atoms
?? g -------------------- 3.8x10²⁴ atoms
(3.8x10²⁴) x 39.948 / 6.02x10²³ => 250 g
hope this helps!
Answer : The mass of argon will be, 250 grams
Explanation : Given,
Number of atoms of argon = \(3.8\times 10^{24}\)
As we know that, 1 mole of substance contains \(6.022\times 10^{23}\) number of atoms.
First we have to calculate the moles of argon.
As, \(6.022\times 10^{23}\) number of argon atoms present in 1 mole of argon
So, \(3.8\times 10^{24}\) number of argon atoms present in \(\frac{3.8\times 10^{24}}{6.022\times 10^{23}}=6.31\) mole of argon
The moles of argon = 6.31 mole
Now we have to calculate the mass of argon.
\(\text{Mass of }Ar=\text{Moles of }Ar\times \text{Molar mass of }Ar\)
\(\text{Mass of }Ar=(6.31mole)\times (40g/mole)=252.4g\)
The mass of argon = 252.4 grams that is approximately equal to 250 grams.
Therefore, the mass of argon will be, 250 grams.