ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
x=\(\frac{-46+/- \sqrt{46^2-4(-16)(6)} }{2(-16)}\)
x=\(\frac{-46+/- \sqrt{2116+384} }{-32}\)
x=\(\frac{-46+/- \sqrt{2500} }{-32}\)
x=\(\frac{-46+/- 50 }{-32}\)
x=\(\frac{-46+ 50 }{-32}\) or \(\frac{-46- 50 }{-32}\)
x=\(\frac{4}{-32}\) or x=\(\frac{-96}{-32}\)
x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds
