Answer:
The displacement of the bus during the trip is 10.07 km.
Explanation:
Given that,
Time = 0.53 h
Average speed of bus = 19 km/h
We need to calculate the displacement of the bus
Using formula of average velocity
\(v_{av}=\dfrac{D}{t}\)
\(D = v_{avg}\times t\)
Where, D = displacement
t = time
Put the value into the formula
\(D=19\times0.53\)
\(D=10.07\ km\)
Hence, The displacement of the bus during the trip is 10.07 km.
