If f(x) = 3 – 2x and g(x)=1/x+5, what is the value of (f/g)(8)?
f(x) = 3 - 2x
g(x) = 1/(x + 5)
(f/g)(x) = (3 - 2x) / 1/(x + 5) = (3 - 2x)(x + 5)
(f/g)(8) = (3 - 2(8))(8 + 5) = -13 x 13 = -169
Answer:
An Arithmetic Combination states that two functions f and g at any x i.e in the domain of both f and g, with one exception.
The quotient \(\frac{f}{g}\) is not defined at values of x, where g is equal to 0 or we can say that both the functions must be defined at a point for the combination to be defined.
\((f/g)(x) =\) \(\frac{f(x)}{g(x)}\)
Given: f(x) = 3-2x and g(x) = \(\frac{1}{x+5}\)
Then, using arithmetic combination of function definition:
\((f/g)(8)=\frac{f(8)}{g(8)}\) ......[1]
Now, first find the value of f(9) and g(8) ;
f(8) =3-2(8) = 3-16 = -13 and
\(g(8) =\frac{1}{8+5} =\frac{1}{13}\)
Substitute these in equation [1] ;
\((f/g)(8) =\frac{-13}{\frac{1}{13}} = -13 \times 13 =-169\)
Therefore, the value of (f/g)(8) is; -169