Answer:
\(\frac{3(6)-1}{2(6)+1}\text{ or }\frac{18-1}{12+1}\text{ or }\frac{17}{13}\)
Step-by-step explanation:
Given functions,
\(r(x) = 3x -1------(1)\)
\(s(x) = 2x + 1-----(2)\)
\(\because \frac{r}{s}(6)=\frac{r(x)}{s(x)}\)
From equation (1) and (2),
\(\frac{r}{s}(x)=\frac{3x-1}{2x+1}\)
Put x = 6,
\(\frac{r}{s}(6) = \frac{3(6)-1}{2(6)+1}=\frac{18-1}{12+1}=\frac{17}{13}\)
