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The answer is B -3/4

The slope of the given line is required.

The slope is b. \(-\dfrac{3}{4}\)

The given equation is

\(3x+4y=12\)

This is in standard form.

Let us write it in slope intercept form which is done by isolating the value of y.

\(3x+4y=12\\\Rightarrow 4y=12-3x\\\Rightarrow y=\dfrac{12}{4}-\dfrac{3}{4}x\\\Rightarrow y=-\dfrac{3}{4}x+3\)

The slope intercept form is given by

\(y=mx+c\)

where \(m\) is the slope and \(c\) is the y intercept.

So, here the slope is b. \(-\dfrac{3}{4}\)

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