Web Analytics
IEatGrapefruits
Answered

Which equation defines the graph of y=x^2 after it is shifted vertically 3 units down and horizontally 5 units left? Thank you for anyone who helps!


Y=(x-5)^2-3

Y=(x+5)^2-3

Y=(x-3)^2-5

Y=(x+3)^2-5

Verified Answer :

HomertheGenius

The parent function is : y = x².
The new equation:  y = a( x - k )² + h,
where:  a = 1,  k = - 5 ( shifted horizontally 5 units left ),
h = - 3 ( shifted vertically 3 units down ).
Answer:
A ) y = ( x + 5 )² - 3

QueasyUnicorn14

Answer:

B. \(y=(x+5)^{2} -3\)

Step-by-step explanation:

we have \(y=x^{2}\). This is a vertical parabola open upward the vertex is equal to the origin \((0,0)\). The rule of the translation is \((x,y)⇒(x-5,y-3)\) that means the translations is \(5\) units to the left and \(3\) units down. Therefore, the new vertex of the function will be \((0,0)⇒(0-5,0-3)\); \((0,0)⇒(-5,-3)\). The new equation of the parabola in vertex form is equal to \(y=(x+5)^{2} -3\). The answer is B. \(y=(x+5)^{2} -3\)

Related Questions