Answer: \(\dfrac{10}{91}\)
Step-by-step explanation:
Given : The jar contains 5 Snickers, 2 Butterfingers, 4 Almond Joys and 3 Milky Ways.
Total candies in the jar =\(5+2+4+3=14\)
Provability that firsts student select snickers =\(\dfrac{5}{14}\)
Now total candies in jar = 14-1=13
Total snickers remained =5-1=4
Probability that the second student also select snickers=\(\dfrac{4}{13}\)
Then, the probability that the first student picks a Snickers and then the second student also picks a Snickers :-
\(\dfrac{5}{14}\times\dfrac{4}{13}=\dfrac{20}{182}=\dfrac{10}{91}\)
Hence, the required probability = \(\dfrac{10}{91}\)
