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Verified Answer :

Teagey

The simplified answer is 18x5y4z.

calculista

Answer:

\(18x^{5}y^{4}z\)

Step-by-step explanation:

we have

\((6xy^{3}z)(3x^{2} yx^{2})\)

Group terms that contain the same variable

\((6*3)(x*x^{2}*x^{2})(y^{3}*y)(z)\)

Using

\(x^a\cdot x^b=x^{a+b}\)

\((18)(x^{1+2+2})(y^{3+1})(z)\)

\((18)(x^{5})(y^{4})(z)\)

\(18x^{5}y^{4}z\)

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