Web Analytics

A shipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed. By how many standard deviations does a beach ball with a diameter of 26.7 cm differ from the mean?

A-1

B-1.3

C-2

D-3

Verified Answer :

Answer:

A. -1

Step-by-step explanation:

We have been given that a shipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed.  

Since z-score represents that a raw score is how many standard deviation above or below mean.

To solve our given problem we will use z-score formula.

\(z=\frac{x-\mu}{\sigma}\), where,

\(z=\text{z-score}\),

\(x=\text{Raw score}\),

\(\mu=\text{Mean}\),

\(\sigma=\text{Standard deviation}\).

Upon substituting our given values in z-score formula we will get,

\(z=\frac{26.7-28}{1.3}\)

\(z=\frac{-1.3}{1.3}\)

\(z=-1\)

Therefore, a beach ball with a diameter of 26.7 cm differs -1 standard deviation from the mean and option A is the correct choice.