Answer:
1.69g
Explanation:
To solve the problem you need to know the Avogadro´s number and the molar mass of the Platinum.
The Avogadro´s number is \(6.022*10^{23}\frac{atoms}{mol}\). For the platinum it means that there are \(6.022*10^{23}\frac{atoms}{mol}\) atoms of platinum for each mol.
And the molar mass for the platinum is \(195.084\frac{g}{mol}\), that is the mass in grams of each mol of platinum.
So, with this information we can solve the problem as follows:
\(5.22*10^{21}atomsofPt*\frac{1molofPt}{6.022*10^{23}atomsofPt}*\frac{195.084g}{1molofPt}=1.69g\) of Pt
