A number n is more than 9 units from 3. The absolute value inequality is?
Answer:
\(|n-3|>9\)
Step-by-step explanation:
A number n is more than 9 units from 3.
We use number line. find out the number that is 9 units from 3 on the right of 3 and left of 3
3+9 = 12
3 -9 = -6
So 12 and -6 are 9 units from 3
number 'n' is more than 9 units
x <-6 or x>12
we can also write
x-3 <-9 or x-3>9
In general, if x<-a or x>a then absolute inequality is
|x|>a
x-3 <-9 or x-3>9
Absolute value inequality becomes
\(|n-3|>9\)
The absolute value inequality is \(|n-3|>9\).
Given that,
Based on the above information, the calculation is as follows:
3+9 = 12
3 -9 = -6
Therefore 12 and -6 should be 9 units from 3.
Also, n should be more than 9 units.
It can be like
x <-6 or x>12
or
x-3 <-9 or x-3>9
Therefore we conclude that The absolute value inequality is \(|n-3|>9\).
Learn more: brainly.com/question/17429689