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Verified Answer :

Ckaranja

Rewriting the equation in the form y=mx+c
-x+3y=9
3y=x+9
y=\(\frac{1}{3} x+3\)
Gradient is 1/3
Since parallel lines have similar gradients,
\(\frac{y--3}{x--3}= \frac{1}{3}\)
y+3=\(\frac{1}{3} (x+3)\)
y+3=\(\frac{1x}{3} +1\)
y=\(\frac{1x}{3} -2\)

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