Answer : The correct option is, (A) 1
Explanation :
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
The rule apply for the multiplication and division is :
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
The given expression is:
\(\frac{2860kg}{0.915cm^3}\times \frac{1cm^3}{1.0\times 10^6cm^3}\times \frac{1000g}{1kg}\)
\(\Rightarrow 3.125\)
In the given expression, 2860 has 3 significant figures, 0.915 has 3 significant figures, 1000 has 1 significant figure and \(1.0\times 10^6\) has 2 significant figures. From this we conclude that 1 is the least significant figure in this problem. So, the answer should be in 1 significant figure.
Thus, the answer will be \(\Rightarrow 0.3\times 10^1\)
Hence, the correct option is, (A) 1
