I really need help on this question!

The spectrophotometer really measures the percent of light that is transmitted through the solution. The instrument then converts %T (transmittance) into absorbance by using the equation you determined in the pre-lab section. If the absorbance of a sample is 0.85, what is the percent light transmitted through the colored sample at this collected wavelength?

We only used the spectrophotometer to measure the absorbance and never got any %T values. So I have to convert absorbance to transmittance. How do I do this with the given absorbance of 0.85?

Use this formula which is th opposite of the formula used to find absorbance when you have the %T

(10^(-A))×100
where A=absorbance so
(10^(-0.85))×100

Answer Link

Tringa0 Tringa0 · Answer 2 · 2019-09-13T06:27:25-04:00

Answer:

14.12% the percent light transmitted through the colored sample at this collected wavelength.

Explanation:

Formula used to convert absorbance into transmittance is:

\(A=\log \frac{I_o}{I}=-\log[T]\)

\(T=\frac{I}{I_o}\)

where,

A = absorbance of solution

T = Transmittance

\(I_o\) = incident light

\(I\) = transmitted light

Given = A = 0.85

\(0.85=-\log[T]\)

\(T=0.1412\)

\(0.1412=\frac{I}{I_o}\)

\(I=0.1412\times I_o\)

Percentage of light transmitted to color solution:

\(\frac{I}{I_o}\times 100=\frac{0.1412\times I_o}{I_o}\times 100=14.12\%\)

14.12% the percent light transmitted through the colored sample at this collected wavelength.