What is the rate of change and initial value for the linear relation that includes the points shown in the table?


x y

1 10

2 8

3 6

4 4

Initial value: 12, rate of change: −2

Initial value: 8, rate of change: 2

Initial value: 12, rate of change: 2

Initial value 8, rate of change: −2

Verified Answer :

Answer:

Initial value \(12\), rate of change: \(-2\)

Step-by-step explanation:

Step 1

Find the rate of change

we know that

In a linear equation the rate of change is equal to the slope

The formula to calculate the slope between two points is equal to  

\(m=\frac{y2-y1}{x2-x1}\)  

we have

\(A(1,10)\ B(2,8)\)  

Substitute the values  

\(m=\frac{8-10}{2-1}\)

\(m=-2\)  ----> rate of change

Step 2

Find the initial value

The equation of  the line into slope-point form is equal to

\(y-y1=m(x-x1)\)

Substitute

\(y-10=-2(x-1)\)

\(y=-2x+2+10\)\(y=-2x+12\)

The initial value is the value of y when the value of x is equal to zero (is the y-intercept)

\(y=-2*0+12=12\)----> initial value