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ben works part-time in a warehouse. his boss is going to send one employee home early as there is little work. of the 56 employees, 21 are part-time. if the boss picks one employee at random, what are the chances it will be a part-time employee?

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XxNightxLostxX

It would be 21 out of 56. In simplifying terms its 3 out of 8.

Answer: The chances that it will be a part time employees is \(\dfac{3}{8}\)

Step-by-step explanation:

Since we have given that

Total number of employees = 56

Number of part time employees = 21

So, Probability that it will be a part time employee is given by

\(\dfrac{\text{Number of part time employees}}{\text{Total number of employees}}\\\\=\dfrac{21}{56}\\\\=\dfrac{3}{8}\)

Hence, The chances that it will be a part time employees is \(\dfac{3}{8}\)

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