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Verified Answer :

0<4x + 8<12  BADDA-BING-BADDA-BOOM!!! :-)

Answer:

\(0<4x+8<12\)

Step-by-step explanation:

The sum of four times a number and eight is between zero and twelve

For example : x is between a  and b can be written as a<x<b

Now we frame inequality for the given statement

Sum of four times a number and eight

LEt the unknown number be x

four times a number is 4x

Sum of 4x  and 8 is \(4x+8\)

4x+8 lies between 0  and 12. So the inequality becomes

\(0<4x+8<12\)