The missing combinations are H-T-P and C-T-S.
Further explanation
The probability of an event is defined as the possibility of an event occurring against sample space.
\(\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }\)
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Permutation ( Arrangement )
Permutation is the number of ways to arrange objects.
\(\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }\)
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Combination ( Selection )
Combination is the number of ways to select objects.
\(\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }\)
Let us tackle the problem!
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This problem is about Combination.
Peter is selling Hazelnut (H), Chocolate (C), Tiramisu (T), Pistachio (P), and Strawberry (S). Total Combinations will be:
\(^5 C_3 = \frac{5!}{( 5 - 3 )! 3!}\)
\(^5 C_3 = \frac{5!}{ 2 ! 3 !}\)
\(^5 C_3 = 5 \times 4 \div 2\)
\(^5 C_3 = \boxed{10}\)
List of Possible Combinations:
H-C-T
H-C-P
H-C-S
H-T-P
H-T-S
H-P-S
C-T-P
C-T-S
C-P-S
T-P-S
The missing combinations are H-T-P and C-T-S.
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Learn more
- Different Birthdays : https://brainly.com/question/7567074
- Dependent or Independent Events : https://brainly.com/question/12029535
- Mutually exclusive : https://brainly.com/question/3464581
Answer details
Grade: High School
Subject: Mathematics
Chapter: Probability
Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation
