Answer:
Equation of line passing through two given points (0,9) and (3,0) is
y = -3x + 9
Step-by-step explanation:
Given : Two points of line as (0,9) and (3,0)
We have to find the equation of line passing through two given points .
The general form of an equation of line is given by y = mx + c where m is slope and c is y intercept.
Slope between two points is given by formula,
\(\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\)
\(\left(x_1,\:y_1\right)=\left(0,\:9\right),\:\left(x_2,\:y_2\right)=\left(3,\:0\right)\)
\(m=\frac{0-9}{3-0}=-3\)
Put m = -3 in equation y = mx + c
we get , \(y=\left(-3\right)x+c\)
Put (0, 9) in above equation , x= 0 and y = 9
we have,
\(9=\left(-3\right)\cdot \:0+c\)
Simplify, we get, c = 9
Thus, equation of line passing through two given points (0,9) and (3,0) is y = -3x + 9
