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caylus

Hello,

\(\int\limits^2_{-1} {(x+2-x^2)} \, dx = \left[\begin{array}{c} \dfrac{x^2}{2}+2x- \dfrac{x^3}{3}\end{array}\right] ^2 _{-1}\\ = \frac{4}{2} +4 - \frac{8}{3} -( \frac{1}{2} -2+ \frac{1}{3} )\\ = \frac{9}{2} =4+ \frac{1}{2}\)

Answer B

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