Answer:
Option B is correct
\(3\cdot x^4 \cdot y^2 \sqrt{2x}\)
Step-by-step explanation:
Given the expression: \(\sqrt{18x^9y^4}\)
Using exponent rule:
\(\sqrt[n]{x^n} = x\)
we can write:
18 = \(3 \cdot 3 \cdot 2 = 3^2 \cdot 2\)
\(x^9 = x^4\cdot x^4 \cdot x\)
\(y^4 = (y^2)^2\)
then;
\(\sqrt{18x^9y^4}\) = \(\sqrt{3^2 \cdot 2 \cdot x^4 \cdot x^4 \cdot x \cdot (y^2)^2} = 3\cdot x^4 \cdot y^2 \sqrt{2x}\)
Therefore, the following is equal to \(\sqrt{18x^9y^4}\) is \(3\cdot x^4 \cdot y^2 \sqrt{2x}\)
