Answer:
Option B is correct
the values of x-coordinates are 4 and 0
Step-by-step explanation:
Given the system of equations:
\(x^2+y^2=25\) .....[1]
\(y=2x-5\) .....[2]
Substitute equation [2] into [1] we have;
\(x^2+(2x-5)^2 = 25\)
⇒\(x^2+4x^2-20x+25=25\)
Subtract 25 from both sides we have;
\(x^2+4x^2-20x=0\)
Combine like terms;
\(5x^2-20x=0\)
⇒\(5x(x-4)=0\)
By zero product property we have;
x = 0 and x-4 = 0
⇒x = 0 and x = 4
Therefore, the values of x are 4 and 0
