3x-2y=3
How do I solve?
How do I solve?
3x-2y=3
How do I solve?
3x - 2y = 3 Subtract 3x from both sides
-2y = -3x + 3 Divide both sides by -2
y = \(\frac{3}{2}\)x - \(\frac{3}{2}\)
3x-2y=3
3x=2y+3 (add 2y to each side)
3x-3=2y (-3 to each side so your focus is on the ys)
\(\frac{3x-3}{2}\) = y