this would be easer to factor
(x+3)(x+4)=0
x+3=0
x+4=0
x=-3 and -4
bu tif want quadratic
in form
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
ax^2+bx+c=0
1x^2+7x+12=0
a=1
b=7
c=12
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
x=\(\frac{-7+/- \sqrt{7^2-4(1)(12)} }{2(1)}\)
x=\(\frac{-7+/- \sqrt{49-48} }{2}\)
x=\(\frac{-7+/- \sqrt{1} }{2}\)
x=\(\frac{-7+/- 1}{2}\)
x=-6/2 or -8/2
x=-3 or -4
