Answer:
The distance between the points (2,1) and (14,6) on a coordinate plane is 13 units.
Step-by-step explanation:
The distance between two points is
\(D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
It is given that the coordinates of two points are (2,1) and (14,6).
Using distance formula, the distance between two points is
\(D=\sqrt{(14-2)^2+(6-1)^2}\)
On simplification we get,
\(D=\sqrt{(12)^2+(5)^2}\)
\(D=\sqrt{144+25}\)
\(D=\sqrt{169}\)
\(D=13\)
Therefore the distance between the points (2,1) and (14,6) on a coordinate plane is 13 units.
