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CameronK1
CameronK1 CameronK1
  • 27-09-2016
  • Mathematics
Answered

The Answer to number 72

The Answer to number 72 class=

Verified Answer :

Lampa20
Lampa20 Lampa20
  • 07-10-2016

First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8

h = 2568 - 168^2
h = 1024

Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16t^2
-16
t^2 + 256t - 200 = 0  

t1 = 0.82s
t2 = 15.17s

time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2

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