For this case we have the following polynomial:
\(6x ^ 2 + 37x - 60
\)
Rewriting the polynomial in the term of degree 1 we have:
\(6x ^ 2 + 37x - 60 = 6x ^ 2 - 8x + 45x - 60
\)
Then, we group the expression obtained as:
\((6x ^ 2 - 8x) + (45x - 60)
\)
In the first parenthesis we do 2x common factor.
In the second parenthesis we make a common factor 15.
We have then:
\(2x (3x - 4) + 15 (3x - 4)
\)
Then, we make a common factor of both parentheses:
\((3x - 4) (2x + 15)
\)
Answer:
The expressions that represent integer factors of \(6x ^ 2 + 37x - 60\) for all values of x are:
\((3x - 4) (2x + 15)
\)
option 1
