The speed or velocity of the car for the total distance travelled in the given time is 8.75m/s
Given the data in the question
- Distance to gas station; \(d_{gas} = 2000m\)
- Distance to shopping mall; \(d_{mall} = 4km = 4000m\)
- Distance back home; \(d_{home} = 4.5km = 4500m\)
- Time taken for the whole trip; \(t = 20min = 1200s\)
First we calculate the total distance travelled
\(d_{Total} = d_{gas}+ d_{mall} + d_{home}\\\\d_{Total} = 2000m + 4000m + 4500m\\\\d_{Total} = 10500m\)
Now, we know that Speed is distance moved or travelled per unit time.
Speed = Distance / Time
\(s = \frac{d}{s}\)
Hence, Speed or Velocity for this problem will be; \(s = \frac{d_{Total}}{t}\)
We substitute in our given values to determine the velocity
\(s = \frac{10500m}{1200s} \\\\s = 8.75 m/s\)
Therefore, The speed or velocity of the car for the total distance travelled in the given time is 8.75m/s
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