Calculate the acceleration of a 2000-kg single engine airplane just before takeoff when the thrust of its engine is 500 N
Acceleration (m/s^2) = Force (N) divided by Mass (kg)
Acceleration = 500 / 2000 = 0.25 m/s^2
Answer:
The acceleration of the single engine airplane is 0.25 m/s^2
Explanation:
The rate of change of velocity is called acceleration.
a = Change in velocity / Change in time
Given data :
\(m = 2000 Kg\\F = 500 N\)\(F = m.a\\\)
On putting values,
\(500= 2000. a\)
\(a =\frac{500}{2000}\)
a = 0.25 m/s^{2}
Hence the acceleration of the airplane is \(0.25 m/s^{2}\)
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