Answer:
\(|\vec A + \vec B| = 50 units\)
Explanation:
As we know that magnitude of two vectors is given as
\(|\vec A + \vec B| = \sqrt{A^2 + B^2 + 2AB cos\theta}\)
here we know that
A = magnitude of vector A
B = magnitude of vector B
\(\theta\) = angle between two vectors
so here we know that
A = 30 units
B = 40 units
angle = 90 degree
so we have
\(|\vec A + \vec B| = \sqrt{30^2 + 40^2 + 2(30)(40)cos90}\)
\(|\vec A + \vec B| = \sqrt{30^2 + 40^2}\)
\(|\vec A + \vec B| = 50 units\)
