Answer:
The remainder is -119
Step-by-step explanation:
\((x^3 - 5x^2+ 14x - 5)\) divide by (x+3)
we use the remainder theorem to find the remainder
We are given with x+3
\(x+3=0, x=-3\)
To find remainder, we substitute -3 for x
\((x^3 - 5x^2+ 14x - 5)\)
\(((-3)^3 - 5(-3)^2+ 14(-3) - 5)\)
\(-27-45-42-5=-119\)
The remainder is -119
